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public static decimal Divide(decimal d1, decimal d2) public bool Equals(decimal value) public override bool Equals(object value) public static bool Equals(decimal d1, decimal d2) public static decimal Floor(decimal d)
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On Mondays, we have a programmers team meeting where we usually discuss what everyone has been doing for the last week and tackle any hot issues. This is our chance to let off steam about any systems that need to be changed or ask any general questions about how all our work fits together. Friday is beer day. At around 5 P.M., we all go down to the in-studio bar, knock back a beer, and eat some cake! A nice finish to a hard-working week. Dave Bryson, Engine Programmer, Electronic Arts UK
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The implementation plan will follow directly from the desired goals for the BIM and the model specifications. This plan describes the deliverables, the process required to produce the desired result from the BIM, and the resources necessary to accomplish these goals. To successfully plan this phase, it is important to know the requirements for information and the associated formats. Each goal should have a clear outline describing the tools and efforts required to realize it. Step 1 is the description of the deliverables, step 2 outlines the required processes to accomplish the deliverables, and step 3 consists of the selection of the persons on the team who are best able to facilitate the first two steps. Things rarely turn out as anticipated, however, and having a detailed plan will help to better respond to the circumstances of the process as they present themselves. The BIM process is a planning and managing process for building construction projects, and it is important for this process itself to be planned and managed carefully. Understanding the BIM Deliverables What exactly is this process supposed to accomplish How can it best be described What are the required BIM project deliverables exactly, and when are they required What are the major milestones in the project s development The answers to these questions will come from the work resulting from the previous sections about the purpose and the specifications of the BIM. When the goals and the level of detail for the information have been determined, it becomes possible to define the deliverables related to these goals. For example, once it has been decided to coordinate the MEP design and installation through the BIM, the required level of detail of the models will be determined by the project s characteristics (e.g., will the pipe hangers and insulation be modeled etc.), and it will become possible to determine the exact deliverables for the necessary processes. It is also helpful to identify both the customer and the supplier in relation to each of the deliverables. This definition will help to focus on the desired quality of the product and its timely completion. In many cases the deliverable for one phase will be the starting point for the next phase in a process. Breaking down the steps and outlining the relationships among all the parts and players help the project team to manage this development and the flow of information. The implementation will be easier to understand and plan
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The following risks represent different objectives an attacker like Henry might have when trying to subvert an authentication system. The attacker usually has a grander goal in mind, such as the embezzlement of a certain amount of money or the capture of certain goods or services. But for the authentication system itself, the attacker s goal is usually limited to one of the three described next: masquerade, multiple identities, or identity theft.
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A brief overview of some of these solutions is found in Table 5-2. The following sections discuss methods available for securing your wireless network.
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// Construct array given its size. public FailSoftArray(int size) { a = new int[size]; Assignment to Length OK Length = size; inside FailSoftArray. } // This is the indexer for FailSoftArray. public int this[int index] { // This is the get accessor. get { if(ok(index)) { ErrFlag = false; return a[index]; } else { ErrFlag = true; return 0; } } // This is the set accessor. set { if(ok(index)) { a[index] = value; ErrFlag = false; } else ErrFlag = true; } } // Return true if index is within bounds. private bool ok(int index) { if(index >= 0 & index < Length) return true; return false; } } // Demonstrate the auto-implemented Length property. class AutoImpPropertyFSDemo { static void Main() { FailSoftArray fs = new FailSoftArray(5); int x; // Can read Length. for(int i=0; i < (fs.Length); i++) fs[i] = i*10; for(int i=0; i < (fs.Length); i++) { x = fs[i];
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If this design is unacceptable, we may replace the cycloidal cam curve with a simple harmonic curve, other modi ed harmonic, or modi ed trapezoidal curve, keeping the other condition intact. By so doing we can calculate hp = 0.02 2b hp 2 xmax = = 0.04. 2b 2 xmax = h will remain unchanged, but kr becomes equal to 0.2 106 N/m, and Qm becomes equal to approximately 4.0. From Fig. 12.11 we obtain bm = 0.0025. Thus qt - qc = 0.25 and its corresponding peak windup torque is Tm = 45 N-m. Therefore, a change from a cycloidal rise to a harmonic rise reduces the forcing function by about 50 percent. Charts of windup versus time and of radial contact force versus time for this harmonic cam system are given as the solid curves in Figs. 12.18 and 12.19. 12.4.3 Two-Degree-of-Freedom System Let us consider a two-degree-of-freedom closed-track cam follower system with an elastic camshaft and an elastic follower. In Fig. 12.20a we see a schematic of the mechanism. In Fig. 12.20b it is observed that torque
Sometimes you will want to catch all exceptions, no matter the type. To do this, use a catch clause that specifies no exception type at all. This creates a catch all handler that is useful when you want to ensure that all exceptions are handled by your program. For example, here the only catch is the catch all, and it catches both the IndexOutOfRangeException and the DivideByZeroException that is generated by the program:
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Again, from the mean-value theorem of integral calculus, a vector c exists such that q = Vc and vector c, once more, de nes the location of the centroid C of R. Correspondingly, the three components of c in a frame F (O, x, y, z) are given by ci, for i = 1, 2, 3, that is, c = [c1, c2, c3]T. The moment of inertia of R about C is then de ned as IC which then reduces to I xx I C = I xy I xz where
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