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Files can have a 3-character extension, but extensions cannot be used in directory names (unlike DOS, which does allow this). Allowable characters are as follows: A through Z, 0 through 9, and the underline character (_). Alphabetic characters must be uppercase. The directory structure can include a maximum of 8 levels. Version numbers following a lename are optional. Version numbers can range from 1 to 32,767. (Version numbers that appear after lenames are separated by a semicolon. Since UNIX does not permit semicolons to be used as part of a lename, developers typically use some form of conversion to mask these characters from the UNIX operating system.) The total number of characters specifying the path to a le within a series of subdirectories is 256. Directories are sorted alphanumerically. Numerical entries (0 through 9) are sorted rst. Underlines (_) are sorted last.

data les are frequently loaded and unloaded between user computers and mass storage facilities. Many cable television systems operating today have the capacity to deliver high-speed data traf c to users connected to the system. Thus, the transfer of large quantities of data can take place a lot faster by cable operators with available channel capacity. In the past, typical cable operators avoided commercial areas simply because they believed no subscribers were present and decided not to place their systems there. Cable operators interested in expanding their businesses by offering data-communication services to commercial enterprises will have to extend their plants to these areas. In short, they will go where the business opportunities exist. At present, many banks, department store chains, and gas stations, to name a few, use very small aperture terminal (VSAT) systems to provide data-communication services. Most of these systems, however, operate in one direction with the upstream through the local exchange carrier (LEX). Cable systems should be able to provide such services to such customers.

Returns a range in which an element can be inserted into a sequence without disrupting the ordering of the sequence. Fills a range with the specified value. Searches a range for a value and returns an iterator to the first occurrence of the element. Searches a range for a subsequence. It returns an iterator to the end of the subsequence within the range. Finds the first element within a sequence that matches an element within a range. Searches a range for an element for which a user-defined unary predicate returns true. Applies a function to a range of elements. Assign elements in a range the values returned by a generator function. Determines if one sequence includes all of the elements in another sequence. Merges a range with another range. Both ranges must be sorted in increasing order. The resulting sequence is sorted. Exchanges the values pointed to by its two iterator arguments. Alphabetically compares one sequence with another. Finds the first point in the sequence that is not less than a specified value. Constructs a heap from a sequence. Returns the maximum of two values. Returns an iterator to the maximum element within a range. Merges two ordered sequences, placing the result into a third sequence. Returns the minimum of two values. Returns an iterator to the minimum element within a range. Finds first mismatch between the elements in two sequences. Iterators to the two elements are returned. Constructs next permutation of a sequence. Arranges a sequence such that all elements less than a specified element E come before that element and all elements greater than E come after it. Sorts a range. Sorts a range and then copies as many elements as will fit into a resulting sequence.

class Encode { static void Main() { char ch1 = 'H'; char ch2 = 'i'; char ch3 = '!'; int key = 88; Console.WriteLine("Original message: " + ch1 + ch2 + ch3); // Encode the message. ch1 = (char) (ch1 ^ key); ch2 = (char) (ch2 ^ key); ch3 = (char) (ch3 ^ key); Console.WriteLine("Encoded message: " + ch1 + ch2 + ch3); // Decode the message. ch1 = (char) (ch1 ^ key); ch2 = (char) (ch2 ^ key); ch3 = (char) (ch3 ^ key); Console.WriteLine("Decoded message: " + ch1 + ch2 + ch3); } }

// Constructor for Rectangle. public Rectangle(double w, double h) : base(w, h, "rectangle"){ } // Construct a square. public Rectangle(double x) : base(x, "rectangle") { } // Construct a copy of a Rectangle object. public Rectangle(Rectangle ob) : base(ob) { } // Return true if the rectangle is square. public bool IsSquare() { if(Width == Height) return true; return false; } // Override Area() for Rectangle. public override double Area() { return Width * Height; } } class AbsShape { static void Main() { TwoDShape[] shapes = new TwoDShape[4]; shapes[0] shapes[1] shapes[2] shapes[3] = = = = new new new new Triangle("right", 8.0, 12.0); Rectangle(10); Rectangle(10, 4); Triangle(7.0);

In fact one can derive this new formula by applying the product formula to g(x) [f (x)/g(x)]. We leave the details for the interested reader. IV Derivative of a Composition [The Chain Rule]: We calculate the derivative of a composition by [f g(x)] = f (g(x)) g (x). To make optimum use of these four new formulas, we need a library of functions to which to apply them. A Derivatives of Powers of x: k {0, 1, 2, . . .}. If f (x) = x k then f (x) = k x k 1 , where

sweatshirt in the SHOP_FACTS table, because you just added it. If a user were to run a report for the sales category Sweats, he/she would not see this sweatshirt listed if the universe contained a default equi-join. Therefore, you need an outer join on the ARTICLE_ LOOKUP table. To change the existing equi-join to an outer join, do the following: 1. Double-click the join line between SHOP_FACTS and ARTICLE_LOOKUP or right-click and select Join Properties from the pop-up menu. 2. Under Table2, ARTICLE_LOOKUP, select the Outer join check box. 3. Select Parse to ensure the join is valid. 4. Click OK to save the change to the join. 5. Click Save on the Designer toolbar to save the changes to the universe.

= x 2 ex 2x ex + 2ex + C. We leave it to the reader to check this last answer by differentiation. You Try It: Calculate the integral x 2 log x dx.