# Modulation in Software Embed GS1 - 12 in Software Modulation

Fig. 7.18 Measuring AC Voltage
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We start with 12/31/2003 in B1. To make it go up by one month, we add 1 to the MONTH. In C1, we write: = DATE YEAR B1 ,MONTH B1 +1,DAY B1 This will return 1/31/2004 (January 31, 2004). Success! Building on this, let s try the next column again. In D1 we add another digit to the MONTH(C1): = DATE YEAR C1 ,MONTH C1 +1,DAY C1 This returns 3/2/2004 (March 2, 2004). This is not quite right. What s happening The problem arises because January has 31 days and, with this formula, we are asking Excel to give the date for something like February 31, 2004. (We had no trouble with the first formula for January, because that month has the same number of days as December.) Since February in this leap year only has 29 days, Excel keeps counting until the day 31 of February, and comes up with the equivalent March 2. How do we find the ending day of each month, given that months lengths vary Instead of trying to find the ending day of each month, we could look for the first day of the next month and then subtract one day. Since the first day is always day 1, this is quite easy. So January 31 is really February 1 minus 1 day; February 28 is March 1 minus 1 day, and so on. But wait. Since Excel can deal with something like February 31 to return March 2 (or March 3 in a non-leap year), can Excel consider January 31 as being February 0, and February 28 as March 0 Yes, in fact, it can. So now we have a solution for our dating problem. We add an extra month to the month interval we want to go up, but specify 0 for the DAY. Let s have 12/31/2003 in B1 again. In C1, to make the date go up by one month, we write: = DATE YEAR B1 ,MONTH B1 +2,0 to get February 0, 2004, which is 1/31/2004.
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Solution: First rewrite the problem as alx =
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