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ONU ONU OLT ONU (a) Tree topology (b) Bus topology
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ArrayUtils.CopyInsert(99, 2, nums, nums2);
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// Assign a string to an object. str_type str_type::operator=(char *str) { str_type temp; strcpy(string, str); strcpy(temp.string, string); return temp; } // Add a string to an object. str_type str_type::operator+(char *str) { str_type temp; strcpy(temp.string, string); strcat(temp.string, str); return temp; }
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Before leaving the topic of I/O, we will examine a technique useful when reading numeric strings. As you know, WriteLine( ) provides a convenient way to output various types of data to the console, including numeric values of the built-in types, such as int and double. Thus, WriteLine( ) automatically converts numeric values into their human-readable form. However, there is no parallel input method that reads and converts strings containing numeric values into their internal, binary format. For example, there is no version of Read( ) that reads from the keyboard a string such as 100 and then automatically converts it into its corresponding binary value that can be stored in an int variable. Instead, there are other ways to accomplish this task. Perhaps the easiest is to use a method that is defined for all of the built-in numeric types: Parse( ). Before we begin, it is necessary to state an important fact: All of C# s built-in types, such as int and double, are actually just aliases (that is, other names) for structures defined by the .NET Framework. In fact, the C# type and .NET structure type are indistinguishable. One is just another name for the other. Because C# s value types are supported by structures, the value types have members defined for them.
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From an array of ContactInfo, produce a list of EmailAddress objects.
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this statement says add to sum the value of sum plus i, then increment i. Thus, it is the same as this sequence of statements:
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Figure 5-8: LIDB model for 0 plus calling card
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SOLUTION We observe that both the numerator and the denominator of the fraction de ning g tend to 0 as x 2 (i.e., as x tends to 2). Thus the question seems to be indeterminate. However, we may factor the numerator as x 2 4 = (x 2)(x + 2). As long as x = 2 (and these are the only x that we examine when we
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