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1 < 0, x2 24. The tangent line to the curve y = x 3 + x at the point (1, 2) has equation (a) y + 2 = 4(x + 1) (b) y + 2 = 3(x 4) (c) y 1 = 4(x 2) (d) y 4 = 2(x 1) (e) y 2 = 4(x 1) 25. The derivative of the function f (x) = ln x/e x is 1/x ln x (a) ex 1/x + ln x (b) ex ln x 2/x (c) ex ex 1 (d) ln x + 1 ex (e) x e +1 26. If f is an invertible, differentiable function and f (0) = 1 and f (0) = 2 then the derivative of f 1 at the point 1 is (a) 2 (b) 3 (c) 4 (d) 1/3 (e) 1/2 If there is a breach, the cloud provider can respond to the incident with less downtime than if you had to investigate the breach locally. It is easy to build a forensic server online, and it costs almost nothing until it comes into use. If there is a problem, the virtual machine can be cloned for easy offline analysis. Further, many companies don t have a dedicated in-house incident response team. If there is a problem, IT staff have to quickly figure out their new job of taking the server down, quickly investigating, and getting it back online for minimal production downtime. Exploring the C# Library
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FIGURE 1-2 // Encode or decode a message using a simple substitution cipher. using System; class Cipher { static int Main(string[] args) { // See if arguments are present. if(args.Length < 2) { Console.WriteLine("Usage: encode/decode word1 [word2...wordN]"); return 1; // return failure code } // If args present, first arg must be encode or decode. Figure 2.3 shows a circuit consisting of a 15-volt battery and 30-ohm load, resulting in a current of: I = V/RL = 15 volts/30 ohms = 0.5 amp We have placed a series resistor, RV, inside the case of our 50 A ammeter. If we want the ammeter to de ect full scale when the voltage is 15 volts, then Ohm s Law says that the series resistor that limits the current to 50 A must be: IV = V/RV RV = V/IV = 15 volts/0.00005 amp = 300,000 ohms The load imposed on the circuit by our voltmeter one ten-thousandth of the 30-ohm circuit load is clearly negligible. If the circuit load, R L, had been 30,000 ohms instead of 30 ohms, then our voltmeter would have siphoned off 10% of the current, giving a result 10% in error, as well as altering the performance of the circuit. Voltmeters are simply ammeters with internal series resistors of 5,000 to 100,000 ohms per volt of full scale. Downloaded from Digital Engineering Library @ McGraw-Hill (www.digitalengineeringlibrary.com) Copyright 2004 The McGraw-Hill Companies. All rights reserved. Any use is subject to the Terms of Use as given at the website.
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