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It follows that v0 = 0, thus con rming our intuition that the initial velocity is 0. Thus p(t) = 16t 2 + h0 . Now we also know that p(5) = 0; that is, at time t = 5 the ball is at height 0. Thus 0 = p(5) = 16 52 + h0 . We may solve this equation for h0 to determine that h0 = 400. We conclude that p(t) = 16t 2 + 400. Furthermore, p(0) = 400, so the initial height of the ball is 400 feet. You Try It: Suppose that a massive ball falls from a height of 600 feet. After how many seconds will it strike the ground
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In (6.5), s is just a dummy variable of integration. Let s see how this equation works with some examples.
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Appendix B:
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In the following example, customer sales comes from the data warehouse. A count of customer visits is stored in a spreadsheet. You would like to analyze whether or not increased customer visits affect customer sales. 1. From the Desktop Intelligence pull-down menu, select Data | New Data Provider. 2. Choose Access New Data In A Different Way and click Begin. 3. In specifying data access, select Others and then from the drop-down list, choose Personal Data File. Click Finish. 4. Specify the data file and indicate if the first row contains column headings as shown here:
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3. The next page of the wizard, shown in Figure 28-18, gets you right into building
// Display the list. void display() { int t; for(t=0; t<SIZE; t++) { if(*invtry[t].item) { cout << invtry[t].item << '\n'; cout << "Cost: $" << invtry[t].cost; cout << "\nRetail: $"; cout << invtry[t].retail << '\n'; cout << "On hand: " << invtry[t].on_hand; cout << "\nResupply time: "; cout << invtry[t].lead_time << " days\n\n"; } } }
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a (in mph/sec) 1 2 3 4 5 6 7 8 9 10
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ature reading. Linear four-bar linkages transmit the motion to and from the cams, which are held in contact by gravity. The basic spiral contour cam mechanism has been used in instrumentation where it was necessary to generate such quantities as trigonometric functions, ballistic functions, logarithms, probability functions, etc. For example, in multiplication, the input is converted to logarithms, added, and then reconverted to a linear scale by antilogs. This cam contour (Fig. 14.48) is the simplest, most ef cient, most accurate means for linearizing input and output shafts where the motion relationship is a nonlinear function. Contacting spirals, which are generally used, have pure rolling action and are reversible. Also, for pure rolling, the contours of one curve must have an increasing radius and those of the other must be a decreasing one. In other words, the curves will not have a minimum or maximum point within the range needed. The surfaces may be plain, have cross-tapes, or have gear teeth. As stated previously, the given related variables are nonlinear and it is necessary to make scale readings equidistant. For example, measurement of ow of a uid may be determined by the pressure drop across an ori ce. In the control eld, the proportional mechanisms for control are linear, and therefore for best results we must again have equal scale measurements. Let us derive the basic relations for this contour. In Fig. 14.48 we see the two curves in contact. Let q0 qi r0 ri ce = angle rotated by the output driven member, deg = the angle rotated by input driver, deg = radius to point of contact at angle q0, in = radius to the point of contact at angle qi, in = r0 + ri = distance between centers of rotation, in.
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These sampling and encoding techniques were than adapted to compact disc. play on a computer screen. Digitizers typically take several seconds to convert an image, and therefore require that the video picture be perfectly still.
FIGURE 11.17. Spring with mass.
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