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Amanda is normally at the midpoint of moderate self-mastery, and although she rarely responds much lower than this, she can also have responses that are almost at the high self-mastery level. She is warm to those she likes and trusts at work, but more often she is remote. During coaching sessions, Amanda can give emotional responses, but only when she has strong feelings; otherwise, she must be asked about her emotions multiple times before she can answer.
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Because BD+ scrambles the video and audio streams on the disc, some of those guys who slump in their seats in the back of the classroom and only partly pay attention to the teacher but still think they know everything have claimed that managed copy is impeded by the BD+ Media Transform process. What these guys would understand, if they were paying attention, is that the Managed Copy Machine, the component that makes the copy after it has been authorized, acts like a player it carries out AACS authentication and decryption along with BD+ reverse transforms to get proper access to the content before it makes a copy.
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Fifth normal form (5NF) applies to M-way relationships like 4NF. Unlike 4NF, 5 N F in v o l v e s situations w h e n a three-way relationship should be replaced with three binary rela tionships, not two binary relationships as for 4NF. Because situations in which 5 N F applies (as opposed to 4 N F ) are rare, 5 N F is generally not considered a practical normal form. Understanding the details o f 5 N F requires a lot o f intellectual investment, but the return on your study time is rarely applicable. The example in Figure 7.12 demonstrates a situation in which 5 N F could apply. The Au thorization entity type represents authorized combinations o f employees, workstations, and software. This associative entity type has redundancy because it can be divided into three binary relationships as shown in Figure 7.13. If y o u k n o w employees authorized to use
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Figure 5-52. 13. Base Salary Step Plan
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Let s examine the preceding program carefully, beginning with the overloaded operator +. When two objects of type ThreeD are operated on by the + operator, the magnitudes of their respective coordinates are added together, as shown in operator+( ). Notice, however, that this method does not modify the value of either operand. Instead, a new object of type ThreeD, which contains the result of the operation, is returned by the method. To understand why the + operation does not change the contents of either object, think about the standard arithmetic + operation as applied like this: 10 + 12. The outcome of this operation is 22, but neither 10 nor 12 is changed by it. Although no rule prevents an overloaded operator from altering the value of one of its operands, it is best for the actions of an overloaded operator to be consistent with its usual meaning. Notice that operator+( ) returns an object of type ThreeD. Although the method could have returned any valid C# type, the fact that it returns a ThreeD object allows the + operator to be used in compound expressions, such as a+b+c. Here, a+b generates a result that is of type ThreeD. This value can then be added to c. Had any other type of value been generated by a+b, such an expression would not work. Here is another important point: When the coordinates are added together inside operator+( ), the addition of the individual coordinates results in an integer addition. This is because the individual coordinates, x, y, and z, are integer quantities. The fact that the + operator is overloaded for objects of type ThreeD has no effect on the + as it is applied to integer values. Now, look at operator ( ). The operator works just like the + operator except that the order of the parameters is important. Recall that addition is commutative, but subtraction is not. (That is, A B is not the same as B A!) For all binary operators, the first parameter to an operator method will contain the left operand. The second parameter will contain the one on the right. When implementing overloaded versions of the noncommutative operators, you must remember which operand is on the left and which is on the right.
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Within the realm of X10 Controllers, there are two different types that you can plug into your computer. The first plugs into your computer s RS-232 serial port. This port is the wide, trapezoidal plug on the back of your computer. This
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E32. Copy across to column G. B110. Copy across to column D. IF(ISNUMBER(E110),E110,D112 E111). Copy across to column G. The ISNUMBER function is important here. With this in use, you can bring the account down to zero by entering a 0 in the input. Without the ISNUMBER, entering a 0 will give a FALSE result for the IF statement, and the result is the prior year s number less the amortization for the year. Long-term assets There are two subentry lines for long-term assets, one for % of revenues and the other for % growth. This gives flexibility for defining this account: The first input defines the account as a function of revenues and thus operations, and the second defines the account by growth, as an investment account. B115 B116 C116 B117 E117 IF(B$8,B114/B$8,0). Copy across to column D. na IF(B117,C114/B117 1,0). Copy to column D. B114. Copy across to column D. IF(E114,E114,IF(E115,E115*E$8, D117*(1 E116))). Copy across to column G. This is a nested IF with three levels for calculating the long-term assets. The formula reads row 114 first. If that is 0, then it reads the next row, and so on. B101 B108 B112 B117. Copy this across to column G.
Possible danger from improper grounding, electrical shock or liquid spills, short burn circuits, exposed wires Substances that can irritate the skin or mucus membranes of the respiratory tract Chemicals that can react with and destroy tissue and other materials pollen, moth balls, steel wool, fiber glass, potassium permanganate bleaches such as hydrogen peroxide; acids such as sulfuric acid, hydrochloric acid; bases such as ammonia, sodium hydroxide
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Learning Objectives 249 Overview 249 8.1 Overview of Physical Database Design 250 8.1.1 Storage Level of Databases 250 8.1.2 Objectives and Constraints 251 8.1.3 Inputs, Outputs, and Environment 252 8.1.4 Difficulties 253 8.2 Inputs of Physical Database Design 253 8.2.1 Table Profiles 253 8.2.2 Application Profiles 255 8.3 File Structures 256 8.3.1 Sequential Files 256 8.3.2 Hash Files 257 8.3.3 Multiway Tree (Btrees) Files 259 8.3.4 Bitmap Indexes 266 8.3.5 Summary of File Structures 267 8.4 Query Optimization 268 8.4.1 Translation Tasks 268 8.4.2 Improving Optimization Decisions 271 8.5 Index Selection 274 8.5.1 Problem Definition 274 8.5.2 Trade-offs and Difficulties 276 8.5.3 Selection Rules 277 8.6 Additional Choices in Physical Database Design 280
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