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Ennea-type Structures: Self-Analysis for the Seeker by Claudio Naranjo (Gateways Books & Tapes, 1991).

3. Connect your security cable wires to the siren s wires and make the appropriate splices, as shown in Figure 6-15. If the same color wires are not present on your siren that are present on your cabling, be sure to make note of which wires have been connected together.

The analysis you ve performed throughout this chapter is only as good as the actions you take from the insight you ve gleaned. As a way of fostering collaboration and insight, BusinessObjects XI provides a discussion capability through the InfoView portal. This is not a replacement for e-mail, but rather, a way of storing textual discussions as they relate to individual reports within the BI repository. When corporate e-mail systems are used to discuss BI content, the analysis becomes separate from the BI repository and a report may be sent as a static attachment. The discussion capability in BusinessObjects XI allows you to keep the textual commentary in the same place as the live reports. Figure 19-14 shows a discussion thread around the earlier ranking report. To initiate a discussion: 1. Select a report from the list within InfoView. 2. In the bottom-right corner of your browser, click the up arrow to expand the discussion pane so that it appears as in Figure 19-14. 3. Click New Message. 4. The right portion of the discussion pane displays a new message, inserting your name and date in the Subject box. Modify the Subject line.

The history and clinical appearance of the lesion are very helpful to determine the disposition in this particular case. For the experienced dermoscopist, sequential digital follow-up is one alternative to excision.

When doing circuit analysis with a network that contains resistors, we apply KCL and KVL using Ohm s law to relate the voltage to the current as necessary. The best way to proceed is to look at some examples. EXAMPLE 2-5 Find the three unknown currents shown in Fig. 2-8. SOLUTION We will denote the voltage across each resistor R by VR . First we apply KVL to each of the two panes or loops in the circuit. Going in a clockwise direction, the loop on the left-hand side of Fig. 2-8 gives 7 + V5 = 0 where V5 is the voltage across the 5 resistor in the center. We conclude from KVL that V5 = 7 V Using Ohm s law (2.6) we can nd the current through the .

Solution:

The most interesting sets of points to graph are collections of points that are de ned by an equation. We call such a graph the locus of the equation. We cannot give all the theory of loci here, but instead consider a few examples. See [SCH2] for more on this matter. EXAMPLE 1.13 Sketch the graph of {(x, y): y = x 2 }. SOLUTION It is convenient to make a table of values: x 3 2 1 0 1 2 3 y = x2 9 4 1 0 1 4 9

We know that this last limit (the same as ( )) is the derivative of f at c. We have learned the following:

Discussion: