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if(nums.Length == 0) { Console.WriteLine("Error: no arguments."); return 0; } m = nums[0]; for(int i=1; i < nums.Length; i++) if(nums[i] < m) m = nums[i]; return m; } } class ParamsDemo { static void Main() { Min ob = new Min(); int min; int a = 10, b = 20; // Call with two values. min = ob.MinVal(a, b); Console.WriteLine("Minimum is " + min); // Call with 3 values. min = ob.MinVal(a, b, -1); Console.WriteLine("Minimum is " + min); // Call with 5 values. min = ob.MinVal(18, 23, 3, 14, 25); Console.WriteLine("Minimum is " + min); // Can call with an int array, too. int[] args = { 45, 67, 34, 9, 112, 8 }; min = ob.MinVal(args); Console.WriteLine("Minimum is " + min); } }
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Here is an expanded version of the previous example program that demonstrates the unary and the ++ operator:
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same name in the base class. Consider this version of the class hierarchy from the preceding example:
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cout << "Enter your guess: "; cin >> guess; if(guess == magic) { cout << "** Right ** "; cout << magic << " is the magic number.\n"; } else { cout << "...Sorry, you're wrong."; if(guess > magic) cout << " Your guess is too high.\n"; else cout << " Your guess is too low.\n"; } } while(guess != magic); return 0; }
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When a disaster has occurred, IT operations need to temporarily take up residence in an alternate processing site while repairs are performed on the original processing site. Once those repairs are completed, IT operations would need to be transitioned back to the main (or replacement) processing facility. You should expect that the procedures for this transition would also be documented (and tested testing is discussed later in this chapter). NOTE Transitioning applications back to the original processing site is not necessarily just a second iteration of the initial move to the hot/warm/cold site. Far from it: the recovery site may have been a skeleton (in capacity, functionality, or both) of its original self. The objective is not necessarily to move the functionality at the recovery site back to the original site, but to restore the original functionality at the original site. Let s look at an example. To continue the Acme Rocket Boots example: their orderentry application at the DR site had only basic, not extended, functions. For instance, customers could not look at order history, and they could not place custom orders; they could only order off-the-shelf products. But when the application is moved back to the primary processing facility, the history of orders accumulated on the DR application needs to be merged into the main order history database, which was not a part of the DR plan.
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a.x = 10; b.x = 20; Console.WriteLine("a.x {0}, b.x {1}", a.x, b.x); a = b; b.x = 30; Console.WriteLine("a.x {0}, b.x {1}", a.x, b.x); } }
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Guidelines and Rulers: 6 The Envelope Tool: 20 Working with Text: s 13 and 14 Filling Objects: 17
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Follicle-stimulating hormone (FSH), luteinizing hormone (LH), and testosterone Ovulatory function
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This section lists the files and folders added to the user profile directory after the application is started for the first time.
8: VLSM
If these operators seem strange to you, keep in mind that they are not needed or used in most programs. They exist primarily to allow some special cases to be handled by the preprocessor.
Router# show interfaces e0 Ethernet 0 is up, line protocol is up Hardware is MCI Ethernet, address is 0000.0c00.1234 (bia 0000.0c00.1234) Internet address is 172.16.16.2, subnet mask is 255.255.255.252 MTU 1500 bytes, BW 10000 Kbit, DLY 100000 usec, rely 255/255, load 1/255 Encapsulation ARPA, loopback not set, keepalive set (10 sec) ARP type: ARPA, ARP Timeout 4:00:00 Last input 0:00:00, output 0:00:00, output hang never Last clearing of "show interface" counters 0:00:00 Output queue 0/40, 0 drops; input queue 0/75, 0 drops Five minute input rate 0 bits/sec, 0 packets/sec Five minute output rate 4000 bits/sec, 8 packets/sec
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int series(void) { static int series_num; series_num = series_num+23; return series_num; }
FIGURE 1.15
Normally an electron beam is invisible to the human eye. However, when the electromagnetic tube contains a low-pressure gas that ionizes upon collision with an electron (emitting light when the ion recombines), the path of the electron beam can be seen. Large coils, known as Helmholtz coils, are mounted around the electromagnetic tube and produce a uniform magnetic field throughout the tube. As the electron beam moves through this magnetic field, it is forced into a circular path. The radius of the circle depends on the speed of the electrons, the strength of the magnetic field, and the mass and charge of the electrons. The velocity, v , of an electron with mass, m, that has been accelerated by a voltage, V, is given by the following equation. 1/2mv 2 eV The radius of the circular path of an electron with velocity v in a magnetic field of strength B is given by the following equation. mv 2/r (e/m) Bev 2V/(B2r 2) Eliminating v in the two equations, and solving for (e/m) yields the following. This is called the e/m ratio equation. On the right hand side, V is the voltage of the electron gun, which is known, and r is the radius of the circular path of the electron beam, which is measurable. Thus, if B (the strength of the magnetic field) is known, e/m can be calculated. Fortunately, the magnetic field due to a pair of Helmholtz coils is known. In fact, the magnetic field B, in Teslas, is proportional to the current I, in amps, going through the coils. B kI Here, k is a constant that depends on the particular coils being used. For a coil of radius R and N number of turns in each coil, k is given by the following equation. k
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