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bandwidth per call is (26.4 Kbps) 1.05 27.72 Kbps. We multiply this rate by the value x in Table 9-8 to determine the bandwidth required between gateways in the IP network. We then use the traffic distribution of Table 9-5 to determine the amount of bandwidth required between pairs of MGs. As for most of the calculations described in this chapter, simple spreadsheet formulas can be used to make the task relatively easy. The resulting bandwidth requirement between MGs is shown in Table 9-9 in megabits per second (Mbps). Signaling and OA&M Bandwidth Not only will traffic take place between MGs, but traffic will exist between MGs and their controlling MGCs. As a rule of thumb, we allocate the same bandwidth for MG-MGC signaling per call as we allocate for RTCP traffic. Unlike RTCP traffic, however, we need to allocate our MG-MGC bandwidth for all calls, not just those that happen to have active speech at a given instant. Next, we allocate bandwidth for MGC-SG signaling. As another rule of thumb, we will allocate the same bandwidth for MGC-SG signaling as we allocate for MG-MGC signaling. In addition to calculating bandwidth for signaling between SGs and MGCs, we must also calculate the number of SS7 links required between our SGs and the STPs of the networks to which we connect. First, we must remember that our SGs will appear to an external network as an STP pair. For connection to an external network, each of our two SGs will connect to two STPs of the external network. Such an approach will create the standard SS7 quad arrangement described in 7, VoIP and SS7 (see Figure 7-4). Second, we will design our SS7 links to run at 40 percent load under normal conditions. By applying such a design rule, we create an environment where we can lose an SS7 link, and a different link can handle the traffic while running at no more than an 80 percent load. Moreover, with a quad arrangement, we can lose a complete STP and still send traffic through the alternative STP of the destination network without overload. An SS7 link that carries ISDN User Part (ISUP) traffic can handle about 30 calls per second. This equates to over 100,000 BHCA. Knowing this number enables us to determine how many SS7 links we will need from our SG pair to each pair of STPs that we connect to. Note that we do not necessarily need to connect to separate STPs or even have separate SS7 links for each trunk group on our network. We need to have separate SS7 links and connect to separate STPs only for traffic to different networks. For example, the LEC in City 1 and the LEC in City 2 might happen to be the same network. In such a case, we might connect to a single STP pair with SS7 links that carry traffic related to both City 1 and
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Type byte sbyte short ushort int uint long ulong Width in Bits 8 8 16 16 32 32 64 64 Range 0 to 255 128 to 127 32,768 to 32,767 0 to 65,535 2,147,483,648 to 2,147,483,647 0 to 4,294,967,295 9,223,372,036,854,775,808 to 9,223,372,036,854,775,807 0 to 18,446,744,073,709,551,615
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A semaphore is similar to a mutex except that it can grant more than one thread access to a shared resource at the same time. Thus, the semaphore is useful when a collection of resources is being synchronized. A semaphore controls access to a shared resource through the use of a counter. If the counter is greater than zero, then access is allowed. If it is zero, access is denied. What the counter is counting are permits. Thus, to access the resource, a thread must be granted a permit from the semaphore. In general, to use a semaphore, the thread that wants access to the shared resource tries to acquire a permit. If the semaphore s counter is greater than zero, the thread acquires a permit, which causes the semaphore s count to be decremented. Otherwise, the thread will block until a permit can be acquired. When the thread no longer needs access to the shared
Description
The k can be determined with the information that after 6 days this particular worker can assemble 5 sewing machmes per day. Substitute N = 5 and z = 6 and solve for k.
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January 2002, followed by the first Blu-ray announcement on February 19.
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unused clusters */ total number of clusters */ number of bytes per sector */ number of sectors per cluster */
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The output from this program is shown here:
Here is a: 1, 2, 3 Here is b: 10, 10, 10 Result of a + b: 11, 12, 13 Result of b + 10: 20, 20, 20
A simple infrared object detector consists of two infrared LEDs, a 40-kHz frequency generator, and a 40-kHz infrared receiver module. For robotic object detection applications, a modulated LED is mounted on both sides of the receiver module pointing slightly away from the receiver module. By alternating which side of the LED is active, you can determine which side the object is on. The schematic shown in Figure 13-10 is for a simple infrared object detector using a few common components. This circuit uses a single 74HC04 CMOS hex inverter to generate the 40-kHz modulated signal, and act as switches to turn on/off the modulated infrared LEDs. The potentiometer R1 is used to adjust the modulated frequency. When selecting the infrared LEDs and the infrared receiver module, make sure that they are both sensitive to the same wavelength. The two most common wavelengths are 880nm and 940nm. For the Sharp detectors that come inside a metal can, the metal case must be grounded to the rest of the circuit. Resistors R4 and R5 can be decreased in value to increase the range of the detector. To turn on the infrared LED, apply 5 volts to the particular LED signal line. To turn it off, ground the signal line. The output of the infrared receiver module is normally high at 5 volts. When it detects the proper modulated infrared light, the output voltage will drop to zero. The Sharp G1U52X and GP1U581Y series infrared receiver modules are the most common, and the Panasonic PNA4602M series infrared receiver modules are becoming more popular since they are less sensitive to visible light than the Sharp detectors, and they are less than half the size of the Sharp detectors.
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