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The C# Language
REPAIR AND RETROFIT METHODS
After we find the range (in kilometers or miles) over which the communications link must reliably transmit information, we must then calculate the wireless link s free-space path loss. This is the loss, in dB, that occurs to an RF signal at a specific frequency over a specific range but it does not account for any impairments. Another figure we must obtain is the fade margin, as mentioned above. This will be required to assure the link of reception reliability during any unexpected, but persistent, atmospheric anomalies and multipath effects. We would also like to find the minimum power that must be available at the receiver s output for proper demodulation within the modem or demodulator, and what SNR is required for the particular modulation and error correction in use. In the following example case, it is being assumed that the RF designer will be told what the maximum transmitter equivalent isotropically radiated power (EIRP) will be. But in order to obtain the necessary BER at the receiver s output, a compromise will normally have to be made between transmitter output power (which must generally be minimized to the lowest level that assures reliable communications), and the receiver s NF and gain versus IMD generation. However, higher-gain antennas and lower-loss coax cable on either the transmit and receive side, or both, can sometimes be an easy way to increase the fade margin. To perform a link budget analysis: 1. Calculate the free-space path loss over the desired link distance. As mentioned, free-space path loss does not include any losses caused by the atmosphere or by multipath, but merely accounts for the inverse square law signal spreading of the RF wavefront as it leaves the transmitting antenna class XYCoord : ITwoDCoord<T> { // Wrong! As the output confirms, the normal constructor is called for object a. However, when a is used to initialize b, the copy constructor is invoked. The use of the copy constructor ensures that b will allocate its own memory. Without the copy constructor, b would simply be an exact copy of a, and a.p would point to the same memory as b.p. Keep in mind that the copy constructor is called only for initializations. For example, the following sequence does not call the copy constructor defined in the preceding program: 3: 14 15 17 19 21 22 23
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