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20 Divisional revenue 1 21 COGS 1 22 SG&A 40 Divisional revenue 2 41 COGS 2 42 SG&A 2 60 Divisional revenue 3 61 COGS 3 62 SG&A 3 63 64 Total revenues 65
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uses Length to copy one array to another while preventing an array overrun and its attendant runtime exception:
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In early versions of the .NET Framework, a thread could be suspended by calling Thread.Suspend( ) and resumed by calling Thread.Resume( ). Today, however, both of these methods are marked as obsolete and should not be used for new code. One reason is that Suspend( ) is inherently dangerous because it can be used to suspend a thread that is currently holding a lock, thus preventing the lock from being released, resulting in deadlock. This can cause a systemwide problem. You must use C# s other synchronization features, such as a mutex, to suspend and resume a thread.
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Be able to compare and contrast the definitions in Tables 23-2 and 23-3: for example, the difference between an inside and outside global address. Understand how dynamic NAT and overloading (use of source TCP/UDP port numbers) works for inside translations and why overloading is necessary in certain situations. Know when PAR is necessary: when you have a single IP address from the ISP, but need Internet users to access internal resources. Be familiar with the advantages and disadvantages of address translation.
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Asymmetry of color and structure Homogeneous global pattern Irregular dots and globules (boxes) Irregular black blotches (black arrows) Bluish-white color (overlying the irregular dark blotches) Hypopigmentation (stars)
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2 is prime. 3 is prime. 4 is not prime. 5 is prime. 6 is not prime. 7 is prime. 8 is not prime. 9 is not prime. Least common factor for 7 and 8 is 1 Least common factor for 100 and 8 is 2 Least common factor for 100 and 75 is 5
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Signal STM-0 STM-1 STM-4 STM-16 STM-64 STM-256 Buildup 3 4 16 64 256 STM-0 STM-1 STM-1 STM-1 STM-1 Operating rate, Mbits/s 51.84 155.52 622.08 2488.32 9953.28 39813.12
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Chromium is an open-source derivation of the Google Chrome web browser.
ln(x/2) = lim ln[(x/2)1/(x 2) ] = lim ln(1 + h/2)1/ h = x 2 x 2 x 2 h 0 lim ln[(1 + h/2)2/ h ]1/2 ln e 1/2 = 1/2. [Here we use the non-trivial
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SELECT FacFirstName, FacLastName, FacCity, FacSalary*1.1 AS IncreasedSalary, FacHireDate FROM Faculty WHERE to_number(to_char(FacHireDate, 'YYYY') ) > 1996
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Figure 27-13. Firewall tab: Add Service Policy Rule Wizard
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1: C# Fundamentals
The LAN Emulation (LE) architecture revolves around LE Clients (LECs) supporting the LE Service on a virtual LAN (Figure 11.12). The procedure starts with LEC initialization to determine which services are available and whether or not to join the emulated LAN. Registration then follows, letting the LE service know which MAC addresses and routing descriptors the LEC represents and how to handle unregistered addresses. When data transmission is requested at the MAC layer, an address resolution request is made to translate the LAN address to the appropriate ATM address. A signaling procedure is then used to set up an ATM virtual channel to the destination LEC. Once established, the VC is used to transfer the MAC packets. The connection will be kept open for a certain period of time so that subsequent packet transfers can avoid further address-resolution and connection-setup stages, thus improving performance. If no further data transfers occur before the period runs out, the connection is released and any future data transfer has to use a new connection. If a broadcast or multicast address is specified, or addresses are unknown, the packets are broadcast to all LECs using the Broadcast and Unknown Server (BUS). Note that the BUS can be used to provide connections for packet transfer while the address resolution process takes place, resulting in a change of connection once resolution is complete. The data transfer itself involves encapsulating the MAC packet with an LE header and checksum in a PDU, which is then segmented using AAL 5 into ATM cells. Different LE data frames are specified for Ethernet-style LANs and Token-Ring LANs, to account for differences such as the reversed transmission order of bits in each octet. LAN Emulation places heavy demands on the ATM network. In addition to the actual transfer of the data across the network, transfer of a LAN packet to an ATM station
Let s examine this program in detail. The program creates three classes. The first is SumArray. It defines the method SumIt( ), which sums an integer array. The second class is MyThread, which uses a static object called sa that is of type SumArray. Thus, only one object of SumArray is shared by all objects of type MyThread. This object is used to obtain the sum of an integer array. Notice that SumArray stores the running total in a field called sum. Thus, if two threads use SumIt( ) concurrently, both will be attempting to use sum to hold the running total. Because this will cause errors, access to SumIt( ) must be synchronized. Finally, the class Sync creates two threads and has them compute the sum of an integer array. Inside SumIt( ), the lock statement prevents simultaneous use of the method by different threads. Notice that lock uses lockOn as the object being synchronized. This is a private object that is used solely for synchronization. Sleep( ) is called to purposely allow a task-switch to occur, if one can but it can t in this case. Because the code within SumIt( ) is locked, it can be used by only one thread at a time. Thus, when the second child thread begins execution, it does not enter SumIt( ) until after the first child thread is done with it. This ensures the correct result is produced. To understand the effects of lock fully, try removing it from the body of SumIt( ). After doing this, SumIt( ) is no longer synchronized, and any number of threads can use it concurrently on the same object. The problem with this is that the running total is stored in sum, which will be changed by each thread that calls SumIt( ). Thus, when two threads call SumIt( ) at the same time on the same object, incorrect results are produced because sum reflects the summation of both threads, mixed together. For example, here is sample output from the program after lock has been removed from SumIt( ):
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