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A list can be sorted by calling the sort( ) member function. The following program creates a list of random integers and then puts the list into sorted order:
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Input, Output, Streams, and Files
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rather than individual rows. If the output relates to individual rows rather than groups o f rows, the G R O U P B Y clause is omitted. W h e n using the G R O U P B Y clause, y o u must include every column from the SELECT clause except for expressions that involve an aggregrate function. Table 4.15 shows the result o f step 2 sorted by CourseNo and O. Of ferNo. N o t e that the columns have been rearranged to make the result easier to read. 4. The fourth step is only necessary if there is a G R O U P B Y clause. The fourth step c o m putes aggregate function(s) for each group o f rows and reduces each group to a single row. A l l rows in a group have the same values for the G R O U P B Y columns. In Table 4.16, there are three groups { < I S 3 2 0 , 3 3 3 3 > , < I S 4 8 0 , 1111>, < I S 4 8 0 , 2 2 2 2 > } . Computed columns are added for aggregate functions in the SELECT and H A V I N G clauses. Table 4 . 1 6 shows two n e w columns for the AVG function in the SELECT clause and the C O U N T function in the H A V I N G clause. N o t e that remaining columns are eliminated at this point because they are not needed in the remaining steps. 5. The fifth step eliminates rows that do not satisfy the H A V I N G condition. Table 4.17 shows that the first row in Table 4 . 1 6 is removed because it fails the HAVING condition. N o t e that the HAVING clause specifies a restriction operation for groups o f rows. The HAVING clause cannot be present without a preceding G R O U P B Y clause. The condi tions in the HAVING clause always relate to groups o f rows, not to individual rows. Typically, conditions in the HAVING clause involve aggregate functions. 6. The sixth step sorts the results according to the O R D E R B Y clause. Note that the O R D E R B Y clause is optional. Table 4.18 shows the result table after sorting. 7. The seventh step performs a final projection. Columns appearing in the result o f step 6 are eliminated if they do not appear in the SELECT clause. Table 4.19 (identical to Table 4.12) shows the result after the projection o f step 6. The Count(*) column is eliminated because it does not appear in SELECT. The seventh step (projection) occurs after the sixth step (sorting) because the O R D E R B Y clause can contain columns that do not ap pear in the SELECT list.
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EXERCISE 19-1 Static Route Configuration
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// Demonstrate a generic stack class. #include <iostream> using namespace std; const int SIZE = 100; // This creates the generic class stack. template <class SType> class stack { SType stck[SIZE]; int tos; public: stack(); ~stack(); void push(SType i); SType pop(); }; // stack's constructor function. template <class SType> stack<SType>::stack() {
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if(SomeEvent != null) SomeEvent();
if(Thrd.Name == "Tick") { for(int i=0; i<5; i++) ttOb.Tick(true); ttOb.Tick(false); } else { for(int i=0; i<5; i++) ttOb.Tock(true); ttOb.Tock(false); } } } class TickingClock { static void Main() { TickTock tt = new TickTock(); MyThread mt1 = new MyThread("Tick", tt); MyThread mt2 = new MyThread("Tock", tt); mt1.Thrd.Join(); mt2.Thrd.Join(); Console.WriteLine("Clock Stopped"); } }
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2. The length of dimension L will be 90 degrees. Calculate the length L, in mils, of these 90 degree microstrip elements as in Shorted-Stub Bandpass Filter, above. 3. Calculate the width W of the 60-ohm microstrip elements as in Shortedstub bandpass filter, above. 4. Calculate the length A of the two outer filter elements from the center of the microstrip input/output transmission lines to the ground via: FL Fu
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levels. Pay careful attention to what part of the report you have selected prior to setting these options. I find the process of formatting break levels much easier in the HTML Interactive Viewer, as described in 19, the section Break Options.
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