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another component. If a wrong decision is made during the sequence, the pin gets stuck in the wheel. This device is equipped with an antireverse spring so that an incorrect sequence cannot be corrected by trial and error. A modi ed design with a translating groove cam is discussed next. 15.6.4 Micromechanical Lock II Translating Groove Cam The mechanical lock shown in Fig. 15.10a is more sophisticated than the one just discussed. It has a slider in which there is a groove cam. The slider also has rack teeth so that it can be actuated. A pin runs in the groove and is actuated with an electrostatic comb drive. The slider is engaged with an antireverse pinion to prevent backtracking. The independent actuations of the slider and the pin are coordinated to permit the slider to move its entire course and to release another component. A detailed view of the groove cam is shown in Fig. 15.10b. 15.6.5 Countermeshing Gear Discriminator Device Another MEMS device that acts like a mechanical lock is the gear discriminator shown in Fig. 15.11a. It has three levels of gears with some teeth missing on each of them and the remaining teeth selectively placed. These gears countermesh in the sense that the meshing gear teeth approach each other from opposite directions, unlike conventional gears where the approach for both teeth is in the same direction. Consequently, they need
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When a successor route is no longer available and no feasible successor route exists in the topology table, a multicast EIGRP query is sent to all
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Table 2.2 Notable differences in old and new materials and methods. Old/Existing Construction N/A for original construction Traditional materials used Replacement De ciencies must be established Modern materials used Formwork, pile bent, precast components 16 feet 6 inches standard cross slope and grade Redundant system Widening Not a de cient bridge Rehabilitation Modern inspection methods with ultra high speed 3D laser techniques Special materials used Modern techniques used Limited changes
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orientation. A controlled-energy- ow forming (CEFF) technique can be used for this purpose. This technique is a high-velocity metalworking procedure that has been a production process for several years. Ausforging, a thermomechanical fabrication method, has potential for improving the strength and life of cams. The suitability of candidate steels to the ausforging process must be individually evaluated. Most cam manufacturing speci cations do not designate heat treatment, but rather call for material characteristics, i.e., hardness and grain size, that are controlled by the heattreatment cycle. Hardness is the most in uential heat-treatment induced variable. It is recommended that RC 55-58 be considered the minimum hardness required for critical cam applications. Residual stresses can be reduced by the heat-treatment process or shot peening. No analytical method can predict the amount of residual stress in the subsurface region, although 50,000 psi alternating shear stress has been accepted in the industry for indefinite cam life.
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Crutch Bents/Underpinning o Pumped Concrete/Grout O Under Footing Lower Foundation/Curtain Wall O PIER GEOMETRY MODIFICATION Extended Footings X Sacri cial Piles X FIXED INSTRUMENTATION Sonar Scour Monitor Magnetic Sliding Collar PORTABLE INSTRUMENTATION Physical Probes Sonar Probes VISUAL MONITORING Periodic Inspection Flood Watch
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4. Thinking Critically a. If one of the pieces of glassware is dropped and breaks, why is it necessary to clean up
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14: Introducing LINQ
3. CCOUP 50 to 200 ohms (XC) for a 50-ohm load. Find the necessary value of CCOUP by simulating the oscillator into a 50-ohm load, and use the lowest CCOUP reactance value that will still allow the oscillator to maintain a decent gain margin ( 5). If a high input impedance buffer amplifier follows CCOUP, then CCOUP CC (however, phase noise will go up). 4. Simulate and optimize as explained in Sec. 4.1, Oscillator Simulation.
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The Thevenin equivalent circuit is shown, with the load resistor attached, in Fig. 3-31. The current owing through the resistor is I = The power is P = VI = RI 2 = (5)(0.3)2 = 0.41 A VTH 3.6 = = 0.3 A RTH + RL 83/11 + 5
This chapter reviews key ideas from precalculus. Master this chapter and you will be well-prepared for calculus.
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