Teaching in K 12 Schools in Software

Assign UCC - 12 in Software Teaching in K 12 Schools

6: Object Selection
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Value 10 pf 12 pf 15 pf 18 pf 22 pf 27 pf 33 pf 39 pf 47 pf 58 pf 68 pf 82 pf 100 pf 120 pf 150 pf 180 pf 220 pf 270 pf 330 pf 390 pf 470 pf 560 pf 680 pf 820 pf 0.001 F 0.0012 F (1200 pf) 0.0015 F 0.0018 F (1800 pf) 0.0022 F 0.0027 F 222 272 152 182 Marking 10 or 100 12 or 120 15 or 150 18 or 180 22 or 220 27 or 270 33 or 330 39 or 390 47 or 470 58 or 580 68 or 680 82 or 820 101 121 151 181 221 271 331 391 471 561 681 821 102 122 Value 0.0033 F 0.0039 F 0.0047 F 0.0056 F 0.0068 F 0.0082 F 0.01 F 0.012 F 0.015 F 0.018 F 0.022 F 0.027 F 0.033 F 0.039 F 0.047 F 0.056 F 0.068 F 0.082 F 0.10 F 0.12 F 0.15 f 0.18 F 0.22 F 0.27 F 0.33 F 0.39 F 0.47 F 0.56 F 0.68 F 0.82 F 1 F Marking 332 392 472 562 682 822 103 123 153 183 223 273 333 393 473 563 683 823 104 124 154 184 224 274 334 394 474 564 684 824 105 or 1 F
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PART 4
Absolute value of a complex number The absolute value of a complex number a + jb is the distance from the origin (0, j 0) to the point (a, jb) on the complex-number plane. For a + j 0 when a is positive, the absolute value is a. For a + j 0 when a is negative, the absolute value is a. For a pure imaginary number 0 + jb where b is positive, the absolute value is b. If b is negative, the absolute value of 0 + jb is equal to b. Suppose we want to find the absolute value of 22 j 0. This is a pure real number. It is the same as 22 + j 0, because j0 = 0. Therefore, the absolute value of this complex number is ( 22) = 22. What about the absolute value of 0 j34 This is a pure imaginary number. The value of b is 34, because 0 j34 = 0 + j( 34). Therefore, the absolute value is ( 34) = 34. If a complex number a + jb is neither pure real or pure imaginary, the absolute value must be found by going through a little arithmetic. First, we square both a and b separately. Then we add the squares. Finally, we take the positive square root of that sum. We can write this as a formula:
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