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The extensive collection of text, tables, and figures that comprise the ANSI-41 standard can be imposing at first. Without a clear understanding of its organization, it is difficult to make effective use of the standard. Our goal in this chapter is to facilitate understanding of the ANSI41 specification structure, including how it differs from past revisions of its predecessor IS-41.
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Before you move disks and install them in a computer that is running Windows XP Professional, you must review these guidelines. If you are moving dynamic disks Do not move dynamic disks to computers running Windows 95, Windows 98, Windows Me, Windows NT 4.0 or earlier, or Windows XP Home Edition because these operating systems cannot read dynamic disks. If you want to make the disk readable by an operating system that cannot read dynamic disks, you must use Windows XP Professional or Windows 2000 to back up or move the data to another disk, delete all volumes, and then right-click the dynamic disk and click Convert to Basic Disk. If you are moving disks that contain multidisk volumes Move all disks that contain multidisk volumes, such as spanned and striped volumes, at the same time. If you move only one disk and leave the other disk in the original computer, the data in the striped or spanned volumes becomes inaccessible on both disks. You must move the disks at the same time to ensure the data is accessible on the target computer. For more information about moving multidisk volumes, see Importing Foreign Disks later in this chapter.
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Give yourself 2 points for the above setup and correct answer (this requires a negative sign in the answer). If the setup is partially correct, give yourself 1 point. c. The ideal gas equation should be rearranged to the form P = nRT /V. n = (5.00 g hexane) (1 mol hexane/86.17 g hexane) (12 mol CO2/2 mol hexane) = 0.3481 mol CO2 This answer has an extra significant figure. The mole ratio should match the one given in your balanced equation. You will not be penalized again for an incorrectly balanced equation. You will lose a point if you do not include a hexane-to-CO2 conversion. R = 0.0821 L atm/mol K This value is given in your test booklet. T = 27 + 273 = 300. K You will be penalized if your forget to use the Kelvin temperature. V = 20.0 L P = (0.3481 mol CO2) (0.0821 L atm/mol K) (300. K)/(20.0 L)= 0.429 atm. Give yourself 2 points for the correct setup and answer. Give yourself 1 point if you did everything correctly, except the mole ratio or the Kelvin conversion. data matrix
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Figure 13.4 Setting the SME s state to unavailable using the RegistrationNotification operation.
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Answer: The residual plot shows a definite pattern. If a line was a good model, we would expect to see a more or less random pattern of points about 0. A line is unlikely to be a good model for this data. 3. Consider the following scatterplot. Is the point A an outlier, an influential observation, or both What effect would its removal have on the slope of the regression line
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And now, when you revisit the URL at http://square.localhost/admin/catalog/item/ index, you ll see that you can sort the data set by various fields, in either ascending or descending order. This sorting selection is retained even as you move between the pages of the data set. If no sorting criteria are stated, the route defaults will ensure that the data set is automatically sorted by item ID in ascending order. Figure 7-2 has an example of the output, sorted by grade (look at the URL in your browser address bar to better understand how this works).
2 k = (0.166 mol/L min)/[(0.020 M) (0.030 M)] 4 3 4 2 = 1.3833 10 M/M min = 1.4 10 /M min 4 2 2 The answer could also be reported as 1.4 10 L /mol min. You should not forget that M = mol/L. Give yourself 1 point for the correct numerical value. Give yourself 1 point for the correct units. c. The coefficients from the equation say that for every mole of ClO3 that forms, 2 mol of ClO2 reacted. Thus, the rate of ClO2 is twice the rate of ClO3 . Do not forget that since ClO3 is forming, it has a positive rate, and since ClO2 is reacting it has a negative rate. This gives: 1 [ClO2 ]/ t = [ClO ]/ t 3 2 Rearranging and inserting the rate from experiment 1 gives:
ow many times have you run into this situation You open the paper to find ten ads for the system administrator position you have been seeking, but the ad calls for one to two years of experience. You just earned your MCSE. It s the IT professional s chicken and the egg dilemma: how do you get that first job without having the hands-on experience it requires In 6, we focused on how to address this issue creatively on your r sum . In this chapter, we take a sidestep and provide you with examples of creative ways to get that experience. In this chapter, we cover: Using your training center as a resource Volunteer work Building your own lab Simulations and paid labs Differentiating yourself from the other applicants
Wouldn t it be nice if someone came up with a ready-made tool we could use to monitor workflow events It s great to be able to spit out the tracking records as we did earlier in the chapter, but a nice graphical user interface would be a lot better to work with. And in fact, we re in luck! When you loaded WF, you also loaded a set of samples, and included in the samples is an application called WorkflowMonitor. So for the price of a compilation step and some file finagling, we can have a simple yet graphical event tracking monitor application. Here s what we need to do to compile the application. Compile WorkflowMonitor 1. WorkflowMonitor is part of the workflow samples library that ships with the Windows Software Development Kit (SDK). Copy the file from its installed location to \Workflow\5 and unzip the contents if you ve not already done so in another directory. The file can be found in the following directory:
This switch uses debugging mode, which provides an even greater amount of output. Use this only when trying to troubleshoot specific problems because much of this output is only decipherable by network programming experts. This switch fixes trivial problems that are found.
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Although the Polish government only licensed two GSM carriers in Poland (Era GSM and Plus GSM), these two carriers competed aggressively for subscribers. Table 1-1 shows the effects of the competition in just the first six months of GSM service being available in Poland. Initial services required purchase of a mobile phone ($300 ) and an activation fee ($300 ). Within six months, the activation fee had dropped to $1, phones were heavily discounted, and tens of thousands of users had signed up. By contrast, in America, nationwide roaming was difficult to implement. The FCC s policies created a cellular market comprised of different technologies and competitors in each major market. Unlike GSM, where interconnecting networks was relatively straightforward, U.S.-based cellular networks used different hardware and switches, making interconnection a lengthy and complicated process. Furthermore, local wireless carriers failed to see the benefits of roaming and were more interested in protecting the local market than offering nationwide service. It was not until the late 1990s when the service plans offered by AT&T Wireless and Sprint PCS provided customers with a nationwide footprint and roaming, nearly six years after the GSM counterparts first offered roaming.
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