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EXPLORING QUESTIONS
b. The residual plot indicates that a line is a good model for the data for all years. c. There appears to be an outlier in the data at about 28 years of experience. d. The variability of salaries increases as years of experience increases. e. For each additional year of experience, salary is predicted to increase by about $2141. 27. A wine maker advertises that the mean alcohol content of the wine produced by his winery is 11%. A 95% confidence interval, based on a random sample of 100 bottles of wine yields a confidence interval for the true alcohol content of (10.5, 10.9) Could this interval be used as part of a hypothesis test of the null hypothesis H0: p = 0.11 versus the alternative hypothesis HA: p 0.11 at the 0.05 level or confidence a. No, you cannot use a confidence interval in a hypothesis test. b. Yes, because 0.11 is not contained in the 95% confidence interval, a twosided test at the 0.05 level of significance would provide good evidence that the true mean content is different from 11%. c. No, because we do not know that the distribution is approximately normally distributed. d. Yes, because 0.11 is not contained in the 95% confidence interval, a twosided test at the 0.05 level of significance would fail to reject the null hypothesis. e. No, confidence intervals can only be used in onesided significance tests. 28. Tom s career batting average is 0.265 with a standard deviation of 0.035. Larry s career batting average is 0.283 with a standard deviation of 0.029. The distribution of both averages is approximately normal. They play for different teams and there is reason to believe that their career averages are independent of each other. For any given year, what is the probability that Tom will have a higher batting average than Larry a. b. c. d. e. 0.389 0.345 0.589 0.655 You cannot answer this question since the distribution for the difference between their averages cannot be determined from the data given. Ms. Dianne Williams, President TWI International 850 North Delaware Avenue Philadelphia, PA 09876 Dear Ms. Williams: < php class Sandbox_ExampleController extends Zend_Controller_Action { public function failAction() { // try accessing a nonexistent array element // generates an OutOfBoundsException $cities = array( 'London', 'Washington', 'Paris', 'Delhi' ); $iterator = new ArrayIterator($cities); $iterator>seek(10); } } The correct answer is (a). A 95% confidence interval at 12 2 = 10 degrees of freedom has a critical value of t* = 2.228 (from Table B; if you have a TI84 with the invT function, invT(0.975, 10)= 2.228) The required interval is 0.74 . (2.228)(0.11) = 0.74 0.245. * Datain Combinational Logic Dataout
Notice that all of the other interconnect signal names have names such as modgen_0_11_xx or ix123. There is no corresponding signal name in the source file to specify the signal name; therefore, the synthesis tool generates names for these signals. The netlist can be used to figure out how well the synthesizer implemented a part of the design, or to track down a problem net. It can be very useful to find out why a critical path was implemented too slowly. When the netlist meets the designer s timing, area, power, and other constraints, the next step is to pass the netlist to the gate level simulator. This simulator checks the functionality of the synthesized design.

