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Another charge is loan fees. These can be almost any amount, from nothing (where the fees are absorbed into a higher loan amount or higher interest rate) to many thousands of dollars. While some lenders are very up front about telling you what these fees are, some sneak them in at the last moment. When the loan fees are actual costs, such as for an appraisal or credit report, they are considered justi ed. However, when they are simply added on to give the lender a better yield (total return on the mortgage), they are usually called garbage fees. We ll have more to say about them in 16. If you are primarily interested in the lowest monthly payment and have some cash on hand, look for the lowest interest rates. However, be aware that lenders with low interest rates often make up for it by jacking up the points and fees. It may cost you more to get the loan. On the other hand, if you want to reduce your closing costs and can stand a bit higher monthly payment, look for a lender who charges few to no closing costs and points. You ll usually pay a higher interest rate, but you won t have to come up with as much cash out of pocket.
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All that remains is to write the .+ method. We pass the number of the record we want to display to this method, and it displays the record's <FIRSTNAME> and <LASTNAME> data[md]called the record's fields[md]in the two text fields. We will write this method now. We start the .+ method by getting the XML document's root element (here, d is the document variable; we've made that variable global so that we can reach it in different methods throughout the applet class): void showRecord(int recordNumber)
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[ClO]/ t = 2(0.166 mol/L min)] = 8.332 mol/L min Give yourself 2 points if you got the entire answer correct. You get only 1 point if the sign or units are missing. d. The rate-determining step must match the rate law. One approach is to determine the rate law for each step in the mechanism. This gives: Step 1: Rate = k[ClO2] Step 2: Rate = k[Cl2O4][OH ] = k[Cl2O]2[OH ] 2 Step 3: Rate = k[HClO2][OH ] = k[ClO2][OH ] For steps 2 and 3, the intermediates must be replaced with reactants. Step 2 gives a rate law matching the one derived in part a. Give yourself 1 point if you picked step 2, or if you picked a step with a rate law that matches a wrong answer for part a. Give yourself 1 more point if you explained the substitution of reactants for intermediates. To see if the stoichiometry is correct, simply add the three steps together and cancel the intermediates (materials that appear on both sides of the reaction arrow).
Does this study provide statistical evidence at the = 0.01 level that the vaccines differ in their effectiveness solution: I. Let p1 = the population proportion infected after receiving Vaccine A. Let p2 = the population proportion infected after receiving Vaccine B. H0: p1 p2 = 0. HA: p1 p2 0. II. We will use a two-proportion z-test at a = 0.01. 102 = 0.453, p2 = 95 = 0.333, p1 = 225 285 n1 p1 = 225(0 .453) = 102, n1(1 p1 ) = 225(0 .547 ) = 123, n2 p2 = 285(0 .333) = 95, n2 (1 p2 ) = 225(0 .667 ) = 19 0 .
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