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Microsoft Windows Vista, Windows XP with Service Pack (SP) 2, Windows Server 2003 with SP1, or newer operating system 500 megahertz (MHz) processor or higher 2 gigabyte (GB) storage space (a portion of this disk space will be freed after installation if the original download package is removed from the hard drive) 256 megabytes (MB) RAM CD-ROM or DVD-ROM drive 1024 768 or higher resolution monitor Microsoft Windows or Windows Vista compatible sound card and speakers Microsoft Internet Explorer 6 or newer Microsoft Mouse or compatible pointing device
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// This is the callback method that takes two Int32 parameters. static Object Add(Int32 n1, Int32 n2) { return n1 + n2; } static Object Subtract(Int32 n1, Int32 n2) { return n1 n2; } // This is the callback method that takes one String parameter. static Object NumChars(String s1) { return s1.Length; } static Object Reverse(String s1) { Char[] chars = s1.ToCharArray(); Array.Reverse(chars); return new String(chars); } }
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15. Click Cancel to close the Remote Router Properties dialog box. 16. Log off Computer1 and Computer2.
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Note that the stored procedure returns the person's original age as its return value, so the IDbDataParameter instance to receive this value must be added to the IDbCommand.Parameters property first. With these changes in mind, here's the revised DBDemo.SetAge method:
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Figure 7-1: Control flow diagram for the example of simple cyclomatic complexity in Listing 7-1. Based on the control flow graph, McCabe identifies the formula to calculate cyclomatic complexity for a function as edges - nodes + 2. In the graph in Figure 7-1, nodes appear as shapes, and the edges are the lines connecting the nodes that show potential paths through the program. The nodes in Figure 7-1 labeled A through D show the statements in the function. Using the formula described earlier, there are four nodes, and four edges, or paths between nodes. Analysis shows that the complexity of this function is 2 (edges (4) - nodes (4) + 2 = 2). An accurate shortcut to calculate cyclomatic complexity is simply to count the number of conditional (predicate) statements and add 1. In the preceding example, there is one condition (if (a < 10)), and thus the cyclomatic complexity is 2. The code sample in Listing 7-2 shows a slightly more complex (yet still relatively simple) example. The control flow graph in Figure 7-2 represents this code.
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figure 3 The logged event
Event Logging
protected bool CheckForPalindrome() { if (this.Text != null) { String strControlText = this.Text; String strTextToUpper = null; strTextToUpper = Text.ToUpper(); strControlText = this.StripNonAlphanumerics(strTextToUpper); char[] rgcReverse = strControlText.ToCharArray(); Array.Reverse(rgcReverse); String strReverse = new string(rgcReverse); if (strControlText == strReverse) { return true; } else { return false;
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We ve already looked at one sort of event in Shoes so far. When a button is clicked, for example, the code in the associated code block is run. This is a click event with a callback. For example: do button("Press me") do alert end end This was the first Shoes example in this chapter. A button is presented that, when clicked, brings up an alert dialog box showing the current time. In this section, we re going to dig deeper and look at different types of events and how to use methods associated with different element types. The code shown in the previous button example was concise, but not particularly dynamic. It would be a lot more interesting if we could associate the button element with a
Within Listin g 8-3, the indivi dual
TerritoryDescription=@TerritoryDescription, RegionID=@RegionID WHERE TerritoryID=@TerritoryID return(0) END GO SET QUOTED_IDENTIFIER OFF GO SET ANSI_NULLS ON GO
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