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xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" mc:Ignorable="d" d:DesignHeight="300" d:DesignWidth="400"> <StackPanel x:Name="LayoutRoot" Background="White" Orientation="Horizontal" > <StackPanel> <TextBlock Text="Blurr Effect" FontSize="12" Margin="15,0,0,0"/> <Image Source="lcd.png" Stretch="None" Margin="15,0,0,0" > <Image.Effect> <BlurEffect Radius="5" /> </Image.Effect> </Image> </StackPanel> <StackPanel> <TextBlock Text="DropShadow Effect" FontSize="12" Margin="40,0,0,0"/> <Image Source="lcd.png" Stretch="None" Margin="40,0,0,0" > <Image.Effect> <DropShadowEffect ShadowDepth="8"/> </Image.Effect> </Image> </StackPanel> </UserControl> Now when you run the project, you should see two images. The first image is blurred, and the second one has the drop shadow effect (see Figure 9-16).
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virtual String^ ToString() override { return name; } }; int main() { MyList<R^>^ R_list = gcnew MyList<R^>(); R_list->Add(gcnew R("test1")); R_list->Add(gcnew R("test2")); R_list->Add(gcnew R("test3")); for each (ListNode<R^>^ node in R_list) { Console::WriteLine(node->item); } } You cannot use a naked reference type (as opposed to a handle type) as a type parameter: List<R>^ R_list = gcnew List<R>(); // illegal You can make it work by either making R a value type or using a handle to R as the generic type argument. When writing a generic class that can take either value types or handles, you need to understand something that may be surprising, especially if you re familiar with templates. And that is that regardless of the type argument, you code your generic class with the assumption that the unknown type is a handle. For example, you use the -> operator vs. the . operator for member access, as in Listing 11-12. You wouldn t expect to be able to do this with a pointer or a nonpointer type with the same template class, because different syntax would be required for each, but for generics, the unknown type is treated as if it were a handle, even if the type substituted is a nonhandle type (a value type or a naked reference type). If the type argument is a value type, you could read the code as if the type parameter were a boxed value type. The actual implementation of the generic doesn t incur the overhead of boxing the value type unless a real boxing operation is needed, for example, if the type parameter is converted to Object^ or a method on Object is accessed. Listing 11-12. Assuming an Unknown Type Is a Handle // generic_reference_syntax.cpp interface class I { void F(); }; value struct V : I { virtual void F() {} }; ref struct R : I { virtual void F() {} };
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