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2.2. Sorting a Pivot Field: New Items Out of Order
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Since the code inside the method must write to an output parameter before it can read from it, it is impossible to send data into a method using output parameters. In fact, if there is any execution path through the method that attempts to read the value of an output parameter before the method has assigned it a value, the compiler produces an error message. public void Add2( out int outValue ) { int var1 = outValue + 2; // Error! Can't read from an output parameter } // before it has been assigned to by the method. For example, the following code again shows method MyMethod, but this time using output parameters: class MyClass { public int Val = 20; } class Program { static void { f1 = new f1.Val = f2 = }
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